Table 6. Results of regression analyses--test soils from Mn/ROAD.
A. Frozen condition.
Std
lb/in.2)*
r2
Material
Equation (Mr in
error
n
Clay subgrade sample 1206 (565)
Mr = 1, 087 f (wu )-5.259
Frozen
207
0.99
0.319
Mr = 1, 049 f (wu-g )-2.344
Frozen
207
0.99
0.275
Mr = 1, 052 f (wu- v )-2.929
Frozen
207
0.99
0.262
Clay subgrade sample 1232 (566)
Mr = 905 f (wu )-4.821
Frozen
244
0.98
0.378
Mr = 846 f (wu- g )-2.161
Frozen
244
0.98
0.423
Mr = 848 f (wu- v )-2.633
Frozen
244
0.98
0.394
Class 3 "stockpile"
Mr = 5, 824 f (wu )-2.026
Frozen
186
0.97
0.491
Mr = 5, 488 f (wu- g )-1.076
Frozen
210
0.97
0.507
Mr = 5, 542 f (wu- v )-1.249
Frozen
186
0.97
0.467
Class 4 (taxiway A subbase)
Mr = 2, 826 f (wu )-5.220
Frozen
69
0.92
0.835
Mr = 1, 813 f (wu- g )-1.733
Frozen
85
0.93
0.885
Mr = 1, 652 f (wu- v )-2.813
Frozen
69
0.91
0.916
Class 5 (dense graded stone)
Mr = 11, 320 f (wu )-2.036
Frozen
28
0.97
0.404
Mr = 8, 695 f (wu-g )-1.2814
Frozen
28
0.95
0.511
Mr = 9, 245 f (wu- v )-1.489
Frozen
28
0.97
0.432
Class 6 "stockpile"
Mr = 19, 924 f (wu )-1.243
Frozen
260
0.98
0.372
Mr = 19, 427 f (wu-g )-0.795
Frozen
260
0.98
0.338
Mr = 19, 505 f (wu- v )-0.897
Frozen
260
0.98
0.341
Notes: n =
f(wuv) = wuv/wo
number of test points
r2 =
wuv = volumetric unfrozen
coefficient of determination
Mr =
resilient modulus
water content
σ = stress (lb/in.2)
f(S) =
S/So
f1 (σ) = J1/σo
S=
degree of saturation (%)
f2 (σ) = (J2/τoct) /σo
So =
1.0 %
f3 (σ) = τoct/σo
f(γ) =
γd/γo
γd =
σo = 1.0 lb/in.2
dry density (Mg/m3)
γo =
1.0 Mg/m3
J1 = bulk stress (lb/in.2)
J1 = 3σ3 + σd
f(wu) =
wug/wt
J2 = 2nd stress invariant (lb/in.2)
wug =
gravimetric unfrozen water content
J2 = 3σ32 + 2σ3σd
wt =
gravimetric total water content
τoct = octahedral shear stress (lb/in.2)
f(wug) =
wug/wo
τoct = ( 2 3) σd
wo =
unit water content (1.0)
*Output from equations can be converted to kilopascals through multiplying by 6.895
12
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